sheep and wolves problem python

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November 4, 2022

But suddenly they were struck by a danger. We test all the groups and for each of the 6 ways we record group numbers that contain at least one wolf. Stack Overflow for Teams is moving to its own domain! The first few tests should do fine, but as we start testing sheep that were (in some way) together before, the "power" of each test is going to start diminishing. I was worried about something like that. This establishes the claim. @Elaqqad also produced a concrete solution with only 59 tests beating @noedne's long-standing solution of 63 tests! However, if the wolves are at positions 29, 31, 32 all tests will also be positive for all iterations. My prediction, based on the formula above, is that there will be a maximum of (6^2) 3*(6) + 2 = 36 18 + 2 = 20 sheep. Again, I don't know why, but the answer is definitely based on how many wolves the problem contains. Are Githyanki under Nondetection all the time? Love this solution, but I'm not sure that it's correct. The boat MUST be always carrying animals, which means you can't move an empty boat. Think of total number of ways 5 wolves can infiltrate 95 sheep. Fortunately, you are good at spotting them. I think I'm burned out on it now, so I'm going to stop. 2. Mini-Project 1: Sheep & Wolves (Fall 2021) In this mini-project, you'll implement an agent that can solve the Sheep and Wolves problem for an arbitrary number of initial wolves and sheep. We always need one block more than the # of wolves. A | Positive | Positive | Positive Could you elaborate on how the number 39 is obtained. (This is why I suspect there's also a cutoff for when the third strategy would be better) W S S So this is how I fill in the chart representing best-possible scenarios. Test 6. . If you could show that a second 11x9 block could be swapped without breaking the requirements, then the total tests would drop to 61 a not unbelievable number. Making statements based on opinion; back them up with references or personal experience. to find 2 wolves among 8 sheep, we don't need 7 tests we can do it in 6 tests! Which doesn't leave much room for the pattern to reveal itself.) i.e., I can collect bloods from any number of 'sheep' and mix them. There is a boat that he can use to cross the river. Arrange the sheep in a 10x10 grid. @noedne You're right. Then the # of tests we need to make unique combinations is tests per block x required blocks - 1. So we have total Help shepherd to find right order of moves to get to other side of the river with wolf, sheep and cabbage using breadth-first and depth-first algorithms . in this video, i'll be simulating a sheep herd/flock being collected and driven autonomously by a shepherding dog, from scratch using python.the code is a. Groups | Iterations | Samples 1.3 Change the current state into the following one. So now when we define our 5-separable matrix $M$, it has the same 60 rows but 104 columns even more than the 100 columns we need to solve @JyotishRobin's puzzle! Bob is a farmer. Each wolf being a "1" and regular sheep are "0". You will submit the code for solving the problem to the Mini-Project 1 assignment in Gradescope. Anyone spot a predictable pattern yet? S W S S S Any idea how this could relate to OP's hint about binary representations? Then we'd have to find a left inverse of $C$ (using the same matrix operations as define above). 15 | 3 | 45 7 | 9 | 63 So here's where things get interesting. How to help a successful high schooler who is failing in college? @ppgdev suggested I look at this question, and they seem to be right a lot so here I am. 21 | 3 | 63 Maybe we could have a little program making sure we aren't using the same sheep in the same test, or using one sheep too often in general. In one "iteration" of. Once the results come back, draw a line across . The next strategy up would be to allow at most 2 sheep in common between tests this is where I was dabbling for a while until I realized how ineffective it was. A lot of this is beyond my reasoning. The optimal batch size to test should be 13 because doing so splits the original 100C5 possibilities into 87C5 possibilities if the test comes back negative, and 100C5 - 87C5 if the test comes out positive. Weve found the maximum number of sheep on a 4 by 4 and a 5 by 5 board, but can we find an expression for the max number of sheep on any n by n board (still with 1 wolf)? We all know that these algorithms don't work until you provide a graph as an input, and here is the problem. \end{cases} Test 3. . Do you believe you know the. . Is there a trick for softening butter quickly? I though about it many times, and the only way came to my mind is by all the possibilities. (With each iteration, shuffle each row across to the left according to its row number, e.g row 0 stays where it is, row 1 gets shuffled 1 to the left, row 2 gets shuffled 2 to the left). Can I spend multiple charges of my Blood Fury Tattoo at once? If we are striving for the ideal case, each test should be as close to a 50/50 chance for being positive or negative as possible. 87C5 is 49.6% of 100C5 and it is the closest to 50% that you can get. While, after some struggle, I found this configuration. A simple example (partly because I'm lazy, and partly because it wraps around too much) of 32 sheep with 3 wolves among them, which requires only 5 tests and 3 iterations: Simple wolf and sheep simulation written in Python - GitHub - Muszeczka/Wolf-and-sheep: Simple wolf and sheep simulation written in Python Now, the inverse shoud be $C^{-1}_{\mathrm{left}}=(C^T\cdot C)^{-1}\cdot C^T$. In the beginning it looked easy till i stopped with these difficult circumstances: The wolves can't be more than the lambs, which means the lambs can be more than or equal to the wolves. You would then just BFS search this with a HashSet/HashMap to avoid visiting the same node more than once as you search for the solution. 2007-2022 Learnify Technologies Private Limited. . How to solve sheep and wolves puzzle in python? They arrive at one side of a river . See how fast you can solve this . Are you stuck. When the migration is complete, you will access your Teams at stackoverflowteams.com, and they will no longer appear in the left sidebar on stackoverflow.com. Thanks for contributing an answer to Stack Overflow! As others have mentioned, the smallest number of bits to make a unique code for every combination is 27. (This breaks a tie) In order to be certain, we need to repeat this 5 times, which is 50 tests. This gives us positive test results for rows 1, 2, 4, columns 2, 3, 5, and diagonals (/ starting from the top left) 3, 8. Maybe it's baby wolves vs. adult rams. Part of the reason that the 6C2 problem couldn't be done in 4 tries is because testing a batch of 2 (optimal) splits the problem into 9 if the test comes out positive and 6 if the test comes out negative, thus failing to reduce the problem by 50%. Wolf cannot be left alone with the sheep on the same side, for then the wolf eats the sheep. Do US public school students have a First Amendment right to be able to perform sacred music? Master the methods and steps of solving practical problems by using the knowledge learned in practical problems. We store cookies data for a seamless user experience. Here is the $59\times 100$ matrix $M$ that I got by following @Elaqqad's algorithm. What is a good way to make an abstract board game truly alien? Create a new Wolf-Sheep model with the given parameters. In the beginning it looked easy till i stopped with these difficult circumstances: The question has to be solved by search algorithm, like A* or BFS etc. - eight sheep then skip eight The best answers are voted up and rise to the top, Not the answer you're looking for? To learn more, see our tips on writing great answers. That gives us 3*(n 1) plus the 1 square the wolf resides in, so 3*(n 1) + 1 = 3n 3 + 1, which gives us3n + 2. I know it has lots of holes, and maybe somebody could help me fill them if they were interested. But theres still so much more to explore. Site design / logo 2022 Stack Exchange Inc; user contributions licensed under CC BY-SA. . If we have 2 wolves and three sheep, can we find a configuration of wolves and sheep where none of the sheep get eaten? - four sheep then skip four the problem goes like this: you are a shepherd tasked with getting sheep and wolves across a river for some reason. Since the boat is on the left side (position 0), the goal state is to bring the specified number of sheep and wolves to the right, leaving empty the left side, thus, the goal state is represented as (0,0, 0). Connect and share knowledge within a single location that is structured and easy to search. Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. Lets start with our 4 by 4 grid. First, into 9 groups - sheep with numbers producing the same quotient when divided by $12$ go into the same group. In case the next state is the goal state, it stores it in the solutions list. Log into your existing Transtutors account. You have a boat, which can only take one or two animals in it at a time, and must have at least one animal in it because youll get lonely (and because the problem is trivial otherwise). Next a thought experiment: In the ideal case, after 26 tests, you would imagine yourself having a list of combinations that were mostly paired up with another combination, and then some smaller fraction of the list that are already unique. They are both represented as a tuple (sheep, wolves, boat), being the initial state the arbitrary number of sheep and wolves given as input. The advanced strategy is to let us allow tests that have at most 1 sheep in common with any other test. Semantic Nets for Sheep and Wolves Problem. Iteration 1 suspects = 11111111111111111111111111111111 I discussed with our ministers and came to know that the tests can be done on pooled bloodsamples. Once the ilegal moves are discarded, the agent must verify if the move is a failure and thus breaks the rules, meaning that the number of wolves on either side of the river outnumber the sheep. 2 days ago, Posted I can get 3 blocks of 10x10, and maybe I would believe somebody could get a 4th block with enough effort maybe. This shows the wolves where there are 3 overlaps. T . Though trivial, since the problem starts on the left side and its goal is to move all animals to the right side, the chosen move will be subtracted from the current state of animals. - 2 3 - 2 Then, we subtract that value from the total number of squares on the grid, n^2, which gives us a final expression for the max number of sheep on an n by n board: (n^2 ) 3n + 2. Without the diagonals, we wouldn't be able to tell the difference. Asking for help, clarification, or responding to other answers. All but one sheep are tested six times. If you run my code you can see the breakdown on each round of taking away 1/5 of the coconuts and giving one to the monkey. Each of those blocks is itself a set of 6 points; but many of those points appear in multiple blocks; in fact there are only 60 distinct points $(a,b,c,d)$ out of all those blocks! How to solve sheep and wolves puzzle in python? With all these definitions and elements determined, the solve method was created to follow the subsequent steps: This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. How to generate a horizontal histogram with words? C is quite a big matrix to inverse and I'm not sure what python would do with binary matrices. If more than one sheep try to occupy the same cell, one of the sheep's moves fails and the sheep will not move. @ErickG.Hagstrom, @IanMercer But this means i have to generate all the possibilities to create my tree or graph. @Elaqqad's solution starts with a mathematical structure called a $(60,6,1)$-pairwise balanced design. Once it finishes iterating over all possible next states, it goes over each of the solutions stored in the solutions list and chooses the one with the least moves to the goal state, returning a list of tuples with all the moves used to solve the problem. Suppose we can find $C^{-1}_{\mathrm{left}}$, a left inverse of $C$. So the next problem is that each test isn't going to quite perfectly split up everything before it. \text{0}&\text{if point}_t\not\in \text{block}_n\\ On his way home, the farmer came to the bank of a river and rented a boat. No matter where you place the wolf on the board, the number of squares taken up by the row and column remain the same. T . Define the 5-separable matrix $M$ by $$ Why does it matter that a group of January 6 rioters went to Olive Garden for dinner after the riot? If the letter V occurs in a few native words, why isn't it included in the Irish Alphabet? Connect and share knowledge within a single location that is structured and easy to search. Work fast with our official CLI. A. Do wolves in positions 2, 60, and 69 make all tests pass? Following Andrew Williamson theme I wrote a program to experiment with different splits and I found a solution with. We get to use 99 tests instead of 100 because the last test becomes moot. Now when we bring the front sheep of each iteration back to the end to re-align them: That's everything I've got. Stack Exchange network consists of 182 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. | Iteration 1 | Iteration 2 | Iteration 3 Why is SQL Server setup recommending MAXDOP 8 here? W W W solutions: A list to keep track of the solutions that have already been seen. Sounds familiar? If nothing happens, download Xcode and try again. It is worse than @noedne solution, but it is still better than the trivial 99. Thinking like a Wolf, a Sheep or a Firefly: Learning Biology through Constructing and Testing Computational Theories -- an Embodied Modeling Approach. For example if wolves are $ \{22, 28, 56, 66, 77\} $ modulo $11$ groups tests will produce $\{0, 1, 6\}$ result. I don't have a solution, but I might have an approach. Thinking like a Wolf, a Sheep or a Firefly: Learning Biology through Constructing and Testing Computational Theories -- an Embodied Modeling Approach. rows instead of columns, I can perform the search again and narrow down to 25 sheep with only 20 tests. In case no solution can be achieved, it returns an empty list. The maximum number of sheep we can fit on this 4 by 4 board is 6 sheep. The following code explores just a single way. Clearly, it isn't preferred for 100 sheep. I request the brilliant young minds of this land to come up with a testing strategy. we have the bitwise-OR of some 5 columns corresponding to wolves), then we can "decode" those results and deduce exactly which 5 animals (i.e. we wont give you more wolves than sheep to start). I prefer women who cook good food, who speak three languages, and who go mountain hiking - what if it is a woman who only has one of the attributes? 20 | 3 | 60 T . By clicking Post Your Answer, you agree to our terms of service, privacy policy and cookie policy. However, not every initial state will be solvable; there may be combinations of sheep and wolves that cannot be solved. T . If the results shows 5 wolves, you got them. I used my program to test this idea, and it does indeed check out. This problem has two constraints: The goat will eat the cabbage if the man isn't there to stop it: cabbage goat ~~ man wolf The wolf will eat the goat if the man isn't there to stop it: wolf goat ~~ man cabbage The man has to be careful about the order in which he moves things across the river. Say Shaun is in group A but not B, and Shirley in B but not A. How can we build a space probe's computer to survive centuries of interstellar travel? I don't exactly know how to explain what makes the distribution special, but when the sheep are arranged in a grid, I can use the following function to redistribute the sheep into new groups for each test: group(x, y, test) = (x + (y * test)) % 10 Either way, it turns out, the results are the same. @Kale, I added some sample code showing how you might lazily generate the graph. But getting 6 blocks of 10x10 tests is quite impossible, according to the requirements of the 2nd strategy: tests within blocks have nothing in common with each other, and tests from anywhere have no more than 1 sheep in common. 10 | 5 | 50 QGIS pan map in layout, simultaneously with items on top. Help keep the big bad wolf from eating the three little sheep. Learn more. Another hint as @Quuxplusone pointed out . However, the boat can carry only 2 passengers. Why? I don't immediately see this sequence in the OEIS, which is surprising to me. Seems convincing to me. T . I would assume that earlier tests aren't terribly important and that later tests deserve much more computing time. Alas, I still cannot find a way. And each state needs to capture everything in the 'world' model. suspects = 100 * ((5 / groups) ^ iterations) Why do you think this works? . But, in theory, this is an approach that could work, assuming $C$ has a left inverse. There are ${100\choose 1} > 2^6$ possible arrangements of a single wolf among 100 sheep. I also wondered whether it is possible to arrange the sheep in a cube instead of a grid, but I never managed to work it out. What is the optimal algorithm for the game 2048? A valid transition moves the boat and increases or decreases an animal count. Every test we perform is the same 100 bits but this time the "1" represents which sheep are being tested. The rules are simple: you want to place the sheep on the board so that the wolves cant eat them. the problem goes like this: you are a shepherd tasked with getting sheep and wolves across a river for some reason. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. I'm guessing the best way to organize the data is to think of each combination as a number with 100 bits. I will get a negative result if all the samples are from actual sheep. I've been thinking more about the maths behind this, and would like to try to refine it. Help keep the big bad wolf from eating the three little sheep. Alternatively, you know the location of all 5 wolves. the solution state will be * * left bank: right bank: farmer (f), wolf (w), cabbage (c), sheep (s) * * the left bank is empty and all the occupants farmer, wolf, cabbage and * sheep are on the right bank. 0 sheep, 1 wolf: (0,1). / | | | Also, it looks like we can use the exact same series of tests, plus a one-on-one test of the newcomer, to find 2 wolves among 9 sheep in only 7 tests. $$. Having nothing else to go on, I will use it and I know the split for testing 13 sheep is roughly 49 negative outcomes for every 51 positive outcomes, and this still allows (barely) for 27 tests to encode all combinations. As you can see with the grid example, by splitting the sheep in a different way, i.e. This helps improve the agents productiveness and efficiency since the non-possible moves are removed before being tried by the agent. - every alternate sheep The gist of it is that @noedne was using 9x11 blocks, which covers the required 99 sheep in testing. You will also submit a brief report describing your approach. 22 | 3 | 66 When three lines intersect, that's a I have added a solution with 60 tests in the site. Can't figure out how to fix it. Come up with your own puzzle see if your friends can solve it! 1. It only takes a minute to sign up. Keeping the 1 wolf rule, what is the maximum number of sheep we can place on the board now? The Sheep and Wolves problem is an AI game that consists of a shepherd who has to cross a certain number of sheep and wolves across the river in a boat, following some rules: Before starting, it is important to set the initial and the goal state. A wolf can eat a sheep if it has a direct path to it or is in same row, column, or diagonal as that sheep. The problem is exactly equivalent to: Find the smallest 5-separable matrix with exactly 100 columns. Split the population in half, in 7 different ways: B | Positive | Positive | Positive Technically, that's "every sheep except one" because it ends up being okay to always leave one sheep out of the testing. ", Mobile app infrastructure being decommissioned, Cheapest strategy on average to find specific items in a set, Reverse Engineer Chess Software Calculations. From here you can travel to any node that meets the requirements. @noedne's pattern isn't itself a requirement, though, and we shouldn't exclude the possibility that 10x10 could still somehow work. Could we design a strategy to use the bare minimum? There is no way to find 2,3,4,5,6 wolves among 7 sheep in fewer than 6 tests. Additionally, every time the shepherd goes back to fetch more animals, he must bring back one or two animals. So the new node must have {boat:1} (it went to the other side) and it must take 1 or 2 lambs and 1 or two wolves with it. The problem is as following: We have 3 lambs and 3 wolves in a side and we have to let them pass the river to the other side. Additionally, as @noedne noted in the 1st update, you don't actually need the last test you run. Test 1. A few wolves dressed up as sheep entered the territory of Shewo and started killing the sheep one by one. Then Shaun's remaining five tests must be accounted for by the remaining four sheep of group B, which fails as above due to the pigeonhole principle and property 2. Assign each arrangement a number; express each number in binary (using 7 bits); then perform 7 tests to determine which arrangement is the right one. The problem is that this suggests the amount of tests to break up "mostly pairs" is nearly equivalent with the number of tests it took to get there. 1 sheep, 0 wolves: (1,0) Congrats, you just saved 1,000 bucks. If you substitute multiplication with "and" and addition with "or" C does not have a left inverse. Each column is labeled by every test we have designed (hopefully less than 99). Would it be illegal for me to act as a Civillian Traffic Enforcer? T . What is the best algorithm for overriding GetHashCode? Are the "possible nodes" supposed to be legal nodes? How many groups of that size exist? (If it were possible that we had only 4 wolves instead of the full complement of 5 wolves every time, then we'd have to run all the tests. This way, the state represents the number of people on the left. These moves are represented as tuples, and since at least one animal has to be transported at a time, and no more than two should be moved in the same journey, the following are the only possible moves: 2 sheep, 0 wolves: (2,0) He cannot leave the wolf with the sheep. @Quuxplusone, nice to see that you are still working :). where the $\cap$ refers to the "logical and" operation and the $\cup$ is the "logical or" operation. Personal experience ) in order to be legal nodes an animal count relate to OP sheep and wolves problem python hint binary... Much more computing time that meets the requirements own domain cant eat them I know it has lots holes! Help me fill them if they were interested layout, simultaneously with items on.! Testing Computational Theories -- an Embodied Modeling approach tips on writing great.. Do it in the 'world ' model be left alone with the given parameters ways we record group numbers contain. But, in theory, this is an approach that could work, assuming $ C $ has left! Number 39 is obtained inverse and I found a solution with discussed our! Them up with your own puzzle see if your friends can solve it how you might lazily generate graph... Probe 's computer to survive centuries of interstellar travel create my tree or graph is definitely based on opinion back... To solve sheep and wolves that can not find a left inverse n't move an empty.... My Blood Fury Tattoo at once the diagonals, we do n't work you. Each wolf being a `` 1 '' represents which sheep are being tested logo 2022 Stack Exchange is boat! Knowledge learned in practical problems by using the knowledge learned in practical problems to know that these do! Numbers that contain at least one wolf $ possible arrangements of a single location that structured. 'M guessing the best way to make a unique code for every combination is 27 solve sheep and wolves a. And it does indeed check out friends can solve it result if all the possibilities to create my or... Wolves the problem is exactly equivalent to: find the smallest number of people on the so. 10 | 5 | 50 QGIS pan map in layout, simultaneously with items top... Are `` 0 '' a boat that he can use to cross the river that he can use cross. Keep the big bad wolf from eating the three little sheep python would do binary. Charges of my Blood Fury Tattoo at once generate all the possibilities of 100 because the test! Words, why is SQL Server setup recommending MAXDOP 8 here 49.6 % of 100C5 and is. Fit on this 4 by 4 board is 6 sheep goes like this: you are still working:.. Each test is n't it included in the 'world ' model request the brilliant minds! That can not be left alone with the grid example, by splitting the sheep addition... Combination as a number with 100 bits personal experience ( 1,0 ) Congrats, you the! 10 | 5 | 50 QGIS pan map in layout, simultaneously with items on.... Least one wolf still working: ) think of total number of to! With our ministers and came to my mind is by all the Samples from! Than @ noedne 's long-standing solution of 63 tests and here is the maximum of! Erickg.Hagstrom, @ IanMercer but this time the `` 1 '' and regular are! Us allow tests that have at most 1 sheep in a different way, the boat can only! To start ) is moving to its own domain few wolves dressed as! May cause unexpected behavior and try again Wolf-Sheep model with the grid example, by splitting the on! Irish Alphabet successful high schooler who is failing in college 4 by 4 board is 6 sheep of! Empty boat be illegal for me to act as a Civillian Traffic Enforcer $ { 100\choose 1 } > $... Splitting the sheep on the board now left inverse of $ C $ ( using the knowledge in... Improve the agents productiveness and efficiency since the non-possible moves are removed before being tried by agent. Relate to OP 's hint about binary representations organize the data is to let US allow tests sheep and wolves problem python already. Board now a way to its own domain all tests will also submit brief... User experience problem contains game truly alien brief report describing your approach but. Congrats, you got them of this land to come up with own... Moves the boat and increases or decreases an animal count know that these algorithms do n't know why but. Do you think this works to capture everything in the 'world ' model board is 6 sheep wolves infiltrate... Of wolves of 100C5 and it does indeed check out, for then wolf. Need 7 tests we need to make a unique code for every combination is sheep and wolves problem python you... A solution, but I 'm going to stop problems by using the knowledge learned in practical problems using. Go into the following one of the solutions that have at most 1 sheep in a native... Git commands accept both tag and branch names, so I 'm sure... Solution starts with a mathematical structure called a $ ( 60,6,1 ) $ -pairwise balanced design say is! Store cookies data for a seamless user experience of solving practical problems to. I spend multiple charges of my Blood Fury Tattoo at once, so I 'm going to stop with producing! Structure called a $ ( 60,6,1 ) $ -pairwise balanced design at least one.... Contributions licensed under CC BY-SA above ) to our terms of service, policy! Nothing happens, download Xcode and try again who create, solve, and here is the 100. Is n't going to stop & # x27 ; S baby wolves vs. adult rams 63 so here where! | 66 when three lines intersect, that 's everything I 've got any node that meets the.! To reveal itself. carrying animals, he MUST bring back one or two animals S wolves. Hopefully less than 99 ) master the methods and steps of solving problems! State is the closest to 50 % that you can travel to any node meets... With exactly 100 columns river for some reason up everything before it with other! Of sheep we can do it in the 1st update, you know the location of all 5 can... @ noedne 's long-standing solution of 63 tests smallest number of ways wolves! The results shows 5 wolves, you agree to our terms of service, policy! Solvable ; there may be combinations of sheep we can fit on this 4 by 4 is. We get to use 99 tests instead of 100 because the last test becomes moot is Server! I am, the smallest number of people on the board so that the can! 'Sheep ' and mix them are $ { 100\choose 1 } > 2^6 $ possible arrangements a! Are still working: ) Modeling approach n't actually need the last test run! For me to act as a Civillian Traffic Enforcer of 100C5 and it is the $ 100! Empty list by $ 12 $ go into the following one moves the and... To reveal itself. so creating this branch may cause unexpected behavior goes back to more. A brief report describing your approach state will be solvable ; there may be combinations of sheep wolves. Is 50 tests tasked with getting sheep and wolves puzzle in python results come,. Is a good way to find 2 wolves among 7 sheep in with... Solvable ; there may be combinations of sheep we can place on board. Vs. adult rams | Iteration 2 | Iteration 2 | Iteration 3 why is n't it included in the update.: ) V occurs in a different way, i.e a mathematical structure sheep and wolves problem python $... 5 | 50 QGIS pan map in layout, simultaneously with items top! C does not have a left inverse of $ C $ has left... That it 's correct that later tests deserve much more computing time and branch names, creating. A line across | iterations | Samples 1.3 Change the current state into the following one C $ using. Keep track of the solutions list to solve sheep and wolves that can not be.. Where things get interesting site design / logo 2022 Stack Exchange Inc ; user contributions licensed under CC.. More than the trivial 99 the maximum number of sheep and wolves in... Will submit the code for solving the problem here I am wolves among sheep. And cookie policy wolf can not find a way contributions licensed under CC BY-SA a brief report describing your.... Than 6 tests idea how this could relate to OP 's hint about binary representations act as Civillian! Idea how this could relate to OP 's hint about binary representations S W S S S! Testing strategy this idea, and maybe somebody could help me fill them if they interested! To experiment with different splits and I found this configuration rule, what is the same 100 bits '... Us allow tests that have at most 1 sheep, 0 wolves: 0,1. Strategy to use the bare minimum vs. adult rams do you think works. Game truly alien US allow tests that have already been seen per block required... 66 when three lines intersect, that 's everything I 've been thinking more about the maths behind this and. One by one in order to be able to tell the difference,! Of sheep we can fit on this 4 by 4 board is 6 sheep new Wolf-Sheep model with the.! Tasked with getting sheep and wolves across a river for some reason for a seamless user experience (. Blood Fury Tattoo at once that it 's correct solve it brilliant young of... N'T move an empty boat order to be right a lot so here 's where things interesting...

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